How to draw a Bode plot on semi-log graph
paper
Mr. Akshay Dattatray Shelke
B.E. Electronics and telecommunication
Email: (akky487@gmail.com)
Question:
1)
A unity control feedback system has G(s) =80/s(s+2)(s+20) Draw the
bode plot.
-Step 1:
Arrange G(s)H(s)in time constant form
as follows:
Step 2:
Identify factors of given H(s)G(s):
1) K=2
2) One
pole is at origin. (Because there is ‘s’ in the denominator).
3) Simple pole 1/(1+s/2) with T1 = ½.
Hence wc1 = 1/T1 = 2.
4)
Similarly simple pole 1/(1+s/20) with T2 = 1/20. wc2 = 1/T2 = 20.
Step 3: Magnitude plot analysis:
1) For
K=2, draw a line of 20logK = 20log2 = 6 dB.
2) For
one pole at origin. Straight line of slope -20 dB/decade passing through
intersection point of w=1 and 0 dB. ( Trick to remember: if there is no pole at
origin draw a straight line. For simple pole draw -20dB/decade line, for second
order pole i.e. ‘s^2 term in denominator’ draw -40dB/decade line, for third
order pole (i.e. S^3)draw -60dB/decade line and so on. And always take
intersection point of w=1 and 0 dB. )
3) Shift
intersection point of w=1 and 0 dB on 20logK line and draw parallel to -20
dB/decade line drawn. This will continue as a resultant of K and 1/s till
first corner frequency occurs. i.e. wc2=2.
4) At wc1
= 2, as there is simple pole it will contribute the rate of -20 dB/decade hence
resultant slope after wc1 = 2 becomes -20-20=-40 dB/decade. This is addition of
K, 1/s and 1/(1+s/2). This will continue till it intersects next corner
frequency line i.e. wc2=20.
5) At wc2
= 20, there is simple pole contributing -20dB/ decade and hence resultant slope
after wc2=20 becomes -40-20=-60 dB/decade. This is resultant of overall
G(s)H(s). i.e. G(jw)H(jw) the final slope is -60dB/decade, as there is no other
factor present.
Step 4: Phase angle plot: Convert
G(s)H(s) to G(jw)H(jw)
To draw straight line of -40 dB/decade
and -60 dB/decade from wc1 = 2 and wc2 = 20, draw faint lines of slope -20,
-40, -60 dB/decade from intersection point of w=1 and 0 dB line and just draw
parallel to them from respective points .
Step 5: Bode plot and solution:
Bode plot
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